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提问人:网友d*******1 发布时间:2022年5月1日 21:37
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11-9 在弦上传播的横波,它的波动方程 {y}_{1}=0.1\cos (13t+0.0079x)(\mathrm{S}\mathrm{I}),试写出一个波动方程,使它表示的波能与这列已知的横波叠加形成驻波,并在 x=0 处为波节。

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