综合维修采用（）相结合的方式。A.经常保养B.状态修C.周期修D.大修 .. 十点题库

手术后尿潴留最好选用下列哪种药物治疗( )

A．东莨菪碱
B．速尿
C．新斯的明
D．阿托品

点击查看答案

传播内容的时效性原则是（　　）。

A. B. C. D. E.

点击查看答案

《HSE作业计划书》的建立应以基层组织的人员为主，要充分考虑（）的要求。

A、业主
B、承包商
C、其他相关方
D、都包括

点击查看答案

神经递质发挥作用后被灭活，而激素则可以持续发挥作用。（）

点击查看答案

细辛中含有（）

A.细辛醚 B.黄樟醚 C.甲基丁香酚 D.丁香酚 E.去甲基衡州乌药碱

点击查看答案

温度升高时，种子贮藏的安全含水量（　　）。

A.升高 B.降低 C.不变 D.无影响

点击查看答案

在通用编号系统中，＃5表示的牙位为（）。

A . 右上颌第一前磨牙
B . 左王颌第一前磨牙
C . 右上颌乳中切牙
D . 左上颌乳中切牙

点击查看答案

When the narrator says "I'm sorry I never told him how sorry I was," (Para 12) he means that _____.

A. "I regret that I never apologized to my father before he died" B. "I regret I never really understood what sorry means" C. "I apologized to my father for my reluctance to walk with him" D. "I apologized to my father for my lacking a good heart"

点击查看答案

水泵机组运行时，机组应该平稳，声音应该（）。

点击查看答案

按照现行准则所确定的利润，应该是建立在资产真实价值基础上的资产利用效果的最终体现，应该更加体现企业资产在价值转移、处置以及持有过程中的增值质量，它是预测企业可持续发展潜力的重要依据。

点击查看答案

（）是提高品牌知名度的重要手段。

A.公关
B.品牌培育
C.卷烟销售
D.销售促进

点击查看答案

维生素A及其制剂等遇光不稳定的药物，贮藏条件应该为（）

A.密闭、避光B.密封、干燥处C.熔封、避光D.密封、遮光E.熔封或严封

点击查看答案

Most of the countries that would be customers for natural gas exported from the U.S. are countries that have free trade agreements with the U.S.

点击查看答案

下列给定程序中，函数fun（)的功能是：根据以下公式求n的值，并作为函数值返回。例如，给指定精度的变

下列给定程序中，函数fun()的功能是：根据以下公式求n的值，并作为函数值返回。例如，给指定精度的变量eps输入 0.0005时，应当输出Pi=3.140578。n/2=1+1/3+1/3*2/5+1/3*2/5*3/7+1/3*2/5*3/7*4/9……请改正程序中的错误，使它能得出正确的结果。注意：不要改动main函数，不得增行或删行，也不得更改程序的结构。试题程序：include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

n/2=1+1/3+1/3*2/5+1/3*2/5*3/7+1/3*2/5*3/7*4/9……请改正程序中的错误，使它能得出正确的结果。注意：不要改动main函数，不得增行或删行，也不得更改程序的结构。试题程序：include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

请改正程序中的错误，使它能得出正确的结果。注意：不要改动main函数，不得增行或删行，也不得更改程序的结构。试题程序：include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

注意：不要改动main函数，不得增行或删行，也不得更改程序的结构。试题程序：include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

试题程序：include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

include ＜conio.h＞include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

include ＜stdio.h＞include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

include ＜math.h＞double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

double fun(double eps){double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

{double s,t; int n=t;s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

s=0.0;/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

/*************found**************/t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

t=1;/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

/*************found**************/while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

while(t＞eps){ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

{ s+=t;t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

t=t*n/(2*n+1);n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

n++;}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

}/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

/*************found**************/return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

return (s);}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

}main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

main(){ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

{ double x;printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

printf("\nPlease enter a precision: ");scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

scanf("%1f",&x);printf("\nPi=%1f\n ",fun(x));}

printf("\nPi=%1f\n ",fun(x));}

}

点击查看答案

“将遭受敌意收购的目标公司为了避免遭到敌意收购者的控制而自己寻找善意收购者”的策略是（）

A . 帕克曼式
B . “锡降落伞”策略
C . “白衣骑士”
D . “皇冠上的宝石&rdquo

点击查看答案