题目内容 (请给出正确答案)
提问人:网友13***556 发布时间:2022年3月20日 07:53
[单项选择题]

一般不单根张拉,而需整体张拉的是()预应力钢绞线。

A.先张法

B.后张法

C.缓张法

D.斜拉索

参考答案
十点题库官方参考答案 (由十点题库聘请的专业题库老师提供的解答)
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str为一个字符序列,序列由字符0和1组成。请补充函数 fun(),该函数的功能是:查找该字符序列中0字符
str为一个字符序列,序列由字符0和1组成。请补充函数 fun(),该函数的功能是:查找该字符序列中0字符连续出现的最长长度(即0字符的个数),如果有几个0字符串长度相同,只记录最后一个0字符串的相关信息。通过m和k返回最长0字符串的长度和最后0字符的下标。例如,如果输入“01001000”,结果为:0字符串最长长度为3,起始和结尾下标依次为5、7。注意:部分源程序给出如下.请勿改动主函数main和其他函数中的任何内容,仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序:include<stdio.h>include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

注意:部分源程序给出如下.请勿改动主函数main和其他函数中的任何内容,仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序:include<stdio.h>include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

请勿改动主函数main和其他函数中的任何内容,仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序:include<stdio.h>include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

试题程序:include<stdio.h>include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

include<stdio.h>include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

include<conio.h>define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

define N 80void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

void fun (【 】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int bb[N];char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

char *p=str;*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*m=0;*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*k=0;for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

for(i=0;i<N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

bb[i]=0;i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i=0;while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

while(*(p+i)){if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

if(*(p+i)='0'){【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

【 】i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i++;}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

else{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

j++;i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i++;}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

if (【 】){*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*m=bb[j];*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*k=i-1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

***\n");printf(" %d,%d",k-m+1,k);}

printf(" %d,%d",k-m+1,k);}

}
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肺表面活性物质减少时可导致()
A . 肺弹性阻力减小
B . 肺顺应性增大
C . 肺泡表面张力降低
D . 肺不易扩张
E . 肺易扩张
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访谈式纪录影片
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