一般不单根张拉，而需整体张拉的是（）预应力钢绞线。 A.先张法 B.后张法 C.缓张法 D.斜拉索 .. 十点题库

车辆行驶过程中，驾驶人应当把废纸或废弃物扔到（）。

A.车窗外街道上
B.随车携带的垃圾箱（袋）里
C.无人看管的道路上
D.车内座位下或车厢内

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所有陈列的货品都必须（）面向顾客。

A . A、侧面
B . B、后面
C . C、正面
D . D、上面

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教育培训统计工作的基本程序包括统计设计、统计调查、（）和统计分析。

A．统计资料的准备
B．信息整合
C．统计资料的整理
D．统计信息的确认

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采用中国传统硬木家具生产工艺，用红木制造的一类家具产品称作（）

A.实木家具
B.硬木家具
C.红木家具

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关于双胎妊娠，叙述错误的是（）。

A . 易并发妊娠高血压综合征
B . 易合并羊水过多
C . 易发生胎位异常
D . 易发生过期妊娠
E . 产后易发生子宫收缩乏力性出血

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依赖VitK的凝血因子是哪一组()|血浆PT明显延长时最可能缺乏的是()

A．因子Ⅰ、Ⅲ、Ⅶ、Ⅴ
B．因子Ⅱ、Ⅶ、Ⅸ、Ⅹ
C．因子Ⅰ、Ⅱ、Ⅴ、Ⅶ
D．因子Ⅳ、Ⅴ、Ⅷ、Ⅻ
E．因子Ⅹ、Ⅺ、Ⅷ、Ⅴ

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除解热镇痛药外，可推荐给长期精神紧张的头痛患者应用的处方药是（）。

A.谷维素
B.氟西汀
C.地西泮
D.卡马西平
E.麦角胺咖啡因片

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AP1000反应堆堆芯采用（）盒高性能燃料组件。

A.177
B.193
C.121
D.157

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下列不属于WEB安全性测试的范畴的是（）？

A . A、数据库内容安全性
B . B、客户端内容安全性
C . C、服务器端内容安全性
D . D、日志功能

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已知随机变量X服从二项分布,且期望值为1,方差为0.8。则该二项分布的参数n和p的值分别为:

A. n=5,p=0.2 B. n=2,p=0.5 C. n=4,p=0.25 D. n=1,p=0.8

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项目投资估算对（）起控制作用。A. 工程设计概算B. 项目资金筹措C. 编制固定资产投资计划D. 基本

项目投资估算对（）起控制作用。A. 工程设计概算B. 项目资金筹措C. 编制固定资产投资计划D. 基本预备费

A. 工程设计概算B. 项目资金筹措C. 编制固定资产投资计划D. 基本预备费

B. 项目资金筹措C. 编制固定资产投资计划D. 基本预备费

C. 编制固定资产投资计划D. 基本预备费

D. 基本预备费

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从根本上觉得投资者效益的是什么？

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str为一个字符序列，序列由字符0和1组成。请补充函数 fun（)，该函数的功能是：查找该字符序列中0字符

str为一个字符序列，序列由字符0和1组成。请补充函数 fun()，该函数的功能是：查找该字符序列中0字符连续出现的最长长度(即0字符的个数)，如果有几个0字符串长度相同，只记录最后一个0字符串的相关信息。通过m和k返回最长0字符串的长度和最后0字符的下标。例如，如果输入“01001000”，结果为：0字符串最长长度为3，起始和结尾下标依次为5、7。注意：部分源程序给出如下．请勿改动主函数main和其他函数中的任何内容，仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序：include＜stdio.h＞include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

注意：部分源程序给出如下．请勿改动主函数main和其他函数中的任何内容，仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序：include＜stdio.h＞include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

请勿改动主函数main和其他函数中的任何内容，仅在函数fun()的横线上填入所编写的若干表达式或语句。试题程序：include＜stdio.h＞include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

试题程序：include＜stdio.h＞include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

include＜stdio.h＞include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

include＜conio.h＞define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

define N 80void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

void fun (【】){int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int i, j=0;int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int bb[N];char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

char *p=str;*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*m=0;*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*k=0;for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

for(i=0;i＜N;i++)bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

bb[i]=0;i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i=0;while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

while(*(p+i)){if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

if(*(p+i)＝'0'){【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

【】i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i++;}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

else{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

j++;i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

i++;}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

if (【】){*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*m=bb[j];*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

*k＝i－1;}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

}main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

main(){char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

{char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

char str[N];int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

int m,n,k;clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

clrscr();printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("***input the original string***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

***\n");gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

gets(str);printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("***The Original string ***\n");puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

puts(str);fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

fun(str,&m,&k);printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("\nThe length of '0' is :%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

%d\n",m);printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

printf("*** The suffix of character***\n");printf(" %d,%d",k-m+1,k);}

***\n");printf(" %d,%d",k-m+1,k);}

printf(" %d,%d",k-m+1,k);}

}

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肺表面活性物质减少时可导致（）

A . 肺弹性阻力减小
B . 肺顺应性增大
C . 肺泡表面张力降低
D . 肺不易扩张
E . 肺易扩张

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访谈式纪录影片

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